I have the following equation: Solve[a x^2 + b x + c == 0, x] I want to gain three cases for this equation. If delta be $ b^2 -4ac$ For $ delta>0$ : $ x =(-b + Sqrt[b^2 -4ac])/(2a)$ and $ x =(-b – Sqrt[b^2 – 4ac])/(2a)$ For $ delta=0$ : $ x =(-b)/(2a)$Read more