**`#include<stdio.h> show(int(*q)[4], int row, int col) { int i,j; int *p; for(i=0;i<row;i++){ p = q+i; for(j=0;j<col;j++){ printf(“%d”, *(p+j)); }printf(“\n”); } } main() { int arr[3][4]={ 1,2,3,4, 5,6,7,8, 9,0,1,2 }; show(arr,3,4); }`** Working Well when used p = q+irow+i; instead of p = q+i; but the solution provided has p = q +i; which gives errorRead more