I have a TemporalData object that has td["ValueDimensions"] =3. Right now I only have one sample, K=1. So the following example is the simplest case, dim=3 and K=1. To begin with, I just want to plot each dimension separately. Should be trivial but it seems I have to twist the td object into knots to get the time dimension to show correctly…

 ts = {{{0.`, {1.333999006891247`, 12.053810602014542`,   87.94618939798545`}}, {0.1`, {1.3514434090695817`,   12.093415930914793`,   86.53455823856495`}}, {0.2`, {1.2484079436257138`,   12.25553483931355`,   92.89743502043808`}}, {0.30000000000000004`, \  {1.3781565261854645`, 12.184908506564101`,   84.45147211241067`}}, {0.4`, {1.3285491537059095`,   12.29338463899116`,   87.1154457958651`}}, {0.5`, {1.353124500190124`,   12.328305046121512`,   85.38069968635773`}}, {0.6000000000000001`, {1.4134624696453986`,   12.326915095624361`,   81.70867228313669`}}, {0.7000000000000001`, {1.195964818586219`,   12.60441567097316`,   94.68144692187659`}}, {0.8`, {1.2736346893937893`,   12.587741552453553`,   89.29573476671187`}}, {0.9`, {1.0705151506735828`,   12.853307642920917`,   103.2366857670525`}}, {1.`, {0.9802798326333646`,   13.00862708606569`, 110.54583685327417`}}}} tds = TemporalData[ts] ListLinePlot[td] (* Pols suggests if "ValuesDimension" returns 3 then this would just work *) ListLinePlot[td["Values", 1]] ListLinePlot[td["Values", 2]] ListLinePlot[td["Values", 3]]  (* The following shows on dimension for the one path, but feels wrong on so many levels, e.g. the time dimension has been lost*) tds["ValueList"][[1, All, 1]] // ListLinePlot 

Once I can do this, I’d like to generate (using ItoProcess) K paths instead of just one, and then I’d like to plot each of these.

Would appreciate any hints or tips about how to do this elegantly.