I am learning LISP and I found a better way to do this using a function with just one parameter but (although this code is inefficient), I’m still not sure why this wouldn’t work. I’m trying to have the function n return n!.
(define (fact n) (for n n) ) (define (for x i) ( (if (<= i 1) (- x 0) (begin (set! i (- i 1)) (set! x (* x i)) (for x i)) ) ) ) (print (fact 3))
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