Put forward the argument: the group number order multiplication can prove that any number of even numbers greater than 2 can be equal to the sum of two prime numbers. Let A be an even number, decompose the mass factor A=B*C*D*E*… Set up B, C, D, e… Not the A’s quality factor Square root number A for Chinese A The number of primes hypothesis before A: alpha v As long as the removal of root A before the star until two odd primes, is the sum of two primes equal to A The number of two odd numbers equal to A is: group A/4 B, C, D dreams, E is the quality factor of 330… * (B-1) /B, (C-1) /C, (D-1) /D, (E-1) /E,… B, C, D of imprisonment, not 330 of the quality factor E… * (b-2) /b, (C-2) /c, (D-2) /d, (E-2) /e,… Group number order multiplication, set up the beta group =A/4* (B-1) /B* (C-1) /C* (D-1) /D* (E-1) /E*… * (b-2) /b* (C-2). The number of two primes and the number of correct sets for A are: Gamma 0 < alpha < gamma dreams = alpha + beta gamma, L at least (alpha beta) group and the prime number is equal to A, that any one even greater than 2 can be equal to the sum of two primes The number order multiplication process is as follows: Example: even 330 Decomposition mass factor 330=2*3*5*11 Dreams 330 square root of the number of Chinese 330=18.165 As long as the prime number minus 18.165 r before, until the combined number And the sum of two prime numbers is equal to 330 There are 6 primes in front of 18.16: 3, 5, 7, 11, 13, 17. Two singular and equal to the number of 330 groups are: 330, 4=82.5 1. is the quality factor of 330 3 dreams The number of groups containing phosphonium multiples of 3: 83*1/3=27.666 Correct for 28 groups: 3+327, 9+321, 15+315, 21+309, 27+303, 33+297, 39+291, 45+285, 51+279, 57+273, 63+267, 69+261, 75+255, 81+249, 87+243, 93+237, 99+231, 105+225, 111+219117+213123+207129+201135+195141+189147+183153+177, 159+171165+165 2. is the quality factor of 330 5 dreams The number of groups containing phosphonium multiples of 5: 83*1/5=16.6 Hence no multiples of 5 multiples of 3: 83*1/5-83*1/5*1/3=83*1/5*2/3=11.006 Correct for 11 groups: 5+325, 25+305, 35+295, 55+275, 65+265, 85+245, 95+235115+215, 125+205145+185155+175 The quality factor of 3. or 330 of the 7 dreams The number of groups containing phosphonium multiples of 7: 83*2/7=23.714 In 5, no 7 grades times not multiples of 3: 83*2/7-83*2/7*1/3-83*2/7*1/5*2/3=83*2/7*4/5*2/3=12.647 Correct for 12 groups: 7+323, 49+281, 77+253, 91+239119+211133+197161+169203+127, 217+113259+71287+43301+29, 4. is the quality factor of 330 11 dreams The number of groups containing phosphonium multiples of 11: 83*1/11=7.545 There are no 7, no 5, no 3 multiplier in the 11 multiples. 83*1/11-83*1/11*1/3-83*1/11*1/5*2/3-83*1/11*1/7*4/5*2/3=83*1/11*5/7*4/5*2/3=2.874 Correct for 3 groups: 11+319121+209143+187 The quality factor of 5. or 330 of the 13 dreams The number of groups containing phosphonium multiples of 13: 83*2/13=12.769 There are no 11 in the 13 times, no 7, no 5, no 3 multiplier. 83*2/13-83*2/13*1/3-83*2/13*1/5*2/3-83*2/13*2/7*4/5*2/3-83*2/13*1/11*5/7*4/5*2/3 =83*2/13*10/11*5/7*4/5*2/3=4.422 The correct 5 groups: 13+317143+187221+109247+83299+31, The quality factor of 6. or 330 of the 17 dreams The number of groups containing phosphonium multiples of 17: 83*2/17=9.764 There are no 13 in the 17 times, no 11, no 7, no 5, and no multiple of 3. 83*2/17-83*2/17*1/3-83*2/17*1/5*2/3-83*2/17*2/7*4/5*2/3-83*2/17*1/11*5/7*4/5*2/3-83*2/17*2/13*10/11*5/7*4/5*2/3 =83*2/17*11/13*10/11*5/7*4/5*2/3=2.861 Correct 3 groups: 17+313, 289+41, 323+7 Group number order multiplication, two numbers add and 330, no 17, no 13, no 11, no 7, no 5, no multiple of 3: 83-83*1/3-83*1/5*2/3-83*2/7*4/5*2/3-83*1/11*5/7*4/5*2/3-83*2/13*10/11*5/7*4/5*2/3 – 83*2/17*11/13*10/11*5/7*4/5*2/3 =83*15/17*11/13*10/11*5/7*4/5*2/3=21.460 And the number of correct groups for 330 is 24 groups: 13+317, 17+313, 19+311, 23+307, 37+293, 47+283, 53+277, 59+271, 61+269, 67+263, 73+257, 79+251, 89+241, 97+233101+229, 103+227107+223131+199137+193139+191149+181151+179157+173163+167 0 < alpha < gamma dreams = alpha + beta gamma, * 0 < 24 – 6 = 21.460 = 24 + 6,